In: Statistics and Probability
(a) Let Y be distributed N(0, 1), i.e. the standard normal variable. Calculate P(Y <= 1.96), P(Y <= 0) and P(Y > 0.6772). Bound P(Y > 3).
(b) Let Y be distributed N(1, 4). Calculate P(Y < 1), P(Y > 2), P(1 ≤ Y ≤ 2).
(c) Let Y be distributed χ 2 1 . Calculate P(Y < 1), P(Y > 3.8416) using the results of the first question.
(d) Let Y be distributed χ 2 3 . Calculate P(Y < 7.81), P(Y > 11.34).
Z TABLE:
(a) GIVEN:
Let Y be distributed N(0, 1). Thus Y follows standard normal distribution with mean = 0 and variance =1
{Since Z=(Y-mu)/sigma}
{Using Z table with row value 1.9 and column corresponding to 0.06}
{Using Z table with row value 0.5 and column corresponding to 0.00}
{Since Z=(Y-mu)/sigma}
{Using Z table with row value 0.6 and column corresponding to 0.08}
{Since Z=(Y-mu)/sigma}
{Using Z table with row value 3.0 and column corresponding to 0.00}
(b) GIVEN:
Let Y be distributed N(1, 4). Thus Y follows normal distribution with mean= 1 and variance =4. Thus =2
{Since Z=(Y-mu)/sigma}
{Using Z table with row value 0.0 and column corresponding to 0.00}
{Since Z=(Y-mu)/sigma}
{Using Z table with row value 0.5 and column corresponding to 0.00}
{Since Z=(Y-mu)/sigma}
(c) GIVEN:
Let Y follows with 1 degree of freedom.
{Let Y=Z^2 as square of standard normal distribution gives chi-square distribution. Here Y~ distribution with 1 degree of freedom and Z~N(0,1)}
{Using Z table value with row corresponding to 1.0 and column corresponding to 0.00}
{Using Z table value with row corresponding to 1.9 and column corresponding to 0.06}
(d) GIVEN:
Y follows distribution with 3 degrees of freedom. Then its normal approximation is given by
where n is degrees of freedom of distribution.
{since n=3}
{Using Z table value with row corresponding to 1.9 and column corresponding to 0.06}
{Using Z table value with row corresponding to 3.4 and column corresponding to 0.00}