In: Statistics and Probability
Math & Music (Raw Data, Software
Required):
There is a lot of interest in the relationship between studying
music and studying math. We will look at some sample data that
investigates this relationship. Below are the Math SAT scores from
8 students who studied music through high school and 11 students
who did not. Test the claim that students who study music in high
school have a higher average Math SAT score than those who do not.
Test this claim at the 0.05 significance level.
Studied Music | No Music | |
count | Math SAT Scores (x1) | Math SAT Scores (x2) |
1 | 521 | 480 |
2 | 586 | 535 |
3 | 604 | 553 |
4 | 573 | 537 |
5 | 516 | 480 |
6 | 554 | 513 |
7 | 546 | 495 |
8 | 607 | 556 |
9 | 554 | |
10 | 493 | |
11 | 557 | |
You should be able copy and paste the data directly into your
software program.
(a) The claim is that the difference in population means is positive (μ1 − μ2 > 0). What type of test is this?
This is a right-tailed test.
This is a left-tailed test.
This is a two-tailed test.
(b) Use software to calculate the test statistic. Do not 'pool' the
variance. This means you do not assume equal variances.
Round your answer to 2 decimal places.
t =
(c) Use software to get the P-value of the test statistic.
Round to 4 decimal places.
P-value =
(d) What is the conclusion regarding the null hypothesis?
reject H0
fail to reject H0
(e) Choose the appropriate concluding statement.
The data supports the claim that students who study music in high school have a higher average Math SAT score than those who do not.
There is not enough data to support the claim that students who study music in high school have a higher average Math SAT score than those who do not.
We reject the claim that students who study music in high school have a higher average Math SAT score than those who do not.
We have proven that students who study music in high school have a higher average Math SAT score than those who do not.
Summary statistics: | ||||||||
Variable | Observations | Obs. with missing data | Obs. without missing data | Minimum | Maximum | Mean | Std. deviation | |
Math SAT Scores (x1) | 8 | 0 | 8 | 516.000 | 607.000 | 563.375 | 35.026 | |
Math SAT Scores (x2) | 11 | 0 | 11 | 480.000 | 557.000 | 523.000 | 31.509 | |
t-test for two independent samples / Upper-tailed test: | ||||||||
95% confidence interval on the difference between the means: | ||||||||
[ 13.698, | +Inf [ | |||||||
Difference | 40.375 | |||||||
t (Observed value) | 2.633 | |||||||
t (Critical value) | 1.740 | |||||||
DF | 17 | |||||||
p-value (one-tailed) | 0.009 | |||||||
alpha | 0.05 | |||||||
Test interpretation: | ||||||||
H0: The difference between the means is equal to 0. | ||||||||
Ha: The difference between the means is greater than 0. | ||||||||
As the computed p-value is lower than the significance level alpha=0.05, one should reject the null hypothesis H0, and accept the alternative hypothesis Ha. | ||||||||
(a) The claim is that the difference in population means is positive (μ1 − μ2 > 0). What type of test is this?
This is a right-tailed test.
(b) Use software to calculate the test statistic. Do not 'pool'
the variance. This means you do not assume equal variances.
Round your answer to 2 decimal places.
t =2.63
(d) What is the conclusion regarding the null hypothesis?
reject H0
(e) We have proven that students who study music in high school have a higher average Math SAT score than those who do not.