Question

In: Statistics and Probability

Data: Bob wishes to study the relationship between mean annual temperature (Temp) and the mortality rate...

Data:

Bob wishes to study the relationship between mean annual temperature (Temp) and the mortality rate (SMI) for a type of breast cancer in women at a 5% significance level and collects paired sample data.

SMI   100   96   95   89   89   79   82   72   65   68   53
Temp   50   49   48   47   45   46   44   43   42   40   34

1) Determine predictor variable, x, and response variable, y. What is the response variable?

Group of answer choices

A) y=mean annual temperature (Temp)

B) y=mortality rate (SMI) for a type of breast cancer in women

C) x=mean annual temperature (Temp)

D) x=mortality rate (SMI) for a type of breast cancer in women

2)Calculate r (rounded to the nearest ten-thousandth).

3)Is there sufficient evidence support the claim of linear correlation? Why? (Hint: Complete a linear correlation hypothesis test using Table A-6.)

Group of answer choices

A) There is sufficient evidence to support the claim of linear correlation because the absolute value of r is larger than the critical value from Table A-6 of 0.602.

B) There is not sufficient evidence to support the claim of linear correlation because the absolute value of r is larger than the critical value from Table A-6 of 0.602.

C)There is sufficient evidence to support the claim of linear correlation because the absolute value of r is not larger than the critical value from Table A-6 of 0.735.

D) There is not sufficient evidence to support the claim of linear correlation because the absolute value of r is larger than the critical value from Table A-6 of 0.735.

E) There is sufficient evidence to support the claim of linear correlation because the absolute value of r is not larger than the critical value from Table A-6 of 0.602.

F) There is sufficient evidence to support the claim of linear correlation because the absolute value of r is larger than the critical value from Table A-6 of 0.735.

G) There is not sufficient evidence to support the claim of linear correlation because the absolute value of r is not larger than the critical value from Table A-6 of 0.602.

H) There is not sufficient evidence to support the claim of linear correlation because the absolute value of r is not larger than the critical value from Table A-6 of 0.735.

4)Find the slope of the regression line (rounded to the nearest ten-thousandth).

5)Find the y-intercept of the regression line (rounded to the nearest ten-thousandth).

6) Calculate the best point estimate for the mortality rate (SMI) for a type of breast cancer in women at mean annual temperature (Temp) of 38 (rounded to the nearest ten-thousandth).

7)Construct a prediction interval estimate for SMI at a Temp of 38. What is the value of the lower bound of the interval (rounded to the nearest tenth)?

Solutions

Expert Solution

1)

x = mean annual temperature (Temp)

y = mortality rate (SMI) for a type of breast cancer in women

2)

Correlation coefficient (r) = 0.9 (=CORREL(Xi,Yi)

3)

H0​: ρ = 0

HA​: ρ not = 0

α = 0.05

rc ​= 0.602 (Use r table)

∣r∣ > rc ​= 0.602, Reject H0

There is sufficient evidence to support the claim of linear correlation because the absolute value of r is larger than the critical value from Table A-6 of 0.602.

4)

Excel > Data > Data Analysis > Regression

SUMMARY OUTPUT
Regression Statistics
Multiple R 0.949879808
R Square 0.902271649
Adjusted R Square 0.891412944
Standard Error 4.892296138
Observations 11
ANOVA
df SS MS F Significance F
Regression 1 1988.770765 1988.770765 83.09200753 7.69148E-06
Residual 9 215.4110535 23.9345615
Total 10 2204.181818
Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0%
Intercept -55.62003454 15.0303308 -3.700519655 0.004916604 -89.62100502 -21.61906407 -89.62100502 -21.61906407
Temp 3.073402418 0.337162917 9.115481749 7.69148E-06 2.31068691 3.836117926 2.31068691 3.836117926

Y^ = -55.6 + 3.1*X

the slope of the regression line = 3.1

5)

the y-intercept of the regression line = -55.6

6)

If X = 38

Y^ = -55.6 + 3.1*X

Y^ = -55.6 + 3.1*38 = 62.2

7)

X0 38
Y^ 62.2
X bar 44.3636
MSE 23.9345615
SSxx 210.55 SUM(X-X bar)^2
t c 2.262157163 Use t table
95% PI
LOWER 49.7 Y^-tc*SQRT(MSE*(1+1/n+(X0-Xbar)^2/SSxx))
UPPER 74.7 Y^+tc*SQRT(MSE*(1+1/n+(X0-Xbar)^2/SSxx))

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