find the general solution of the given differential
equation.
1. y'' + y = tan t, 0 < t < π/2
2. y'' + 4y' + 4y = t-2 e-2t , t >
0
find the solution of the given initial value problem.
3. y'' + y' − 2y = 2t, y(0) = 0, y'(0) = 1
A) Find the general solution of the given differential equation.
y'' + 8y' + 16y = t−2e−4t, t > 0
B) Find the general solution of the given differential equation.
y'' − 2y' + y = 9et / (1 + t2)
For the following differential equation
y'' + 9y = sec3x,
(a) Find the general solution yh, for the
corresponding homogeneous ODE.
(b) Use the variation of parameters to find the
particular solution yp.
Find a general solution to the differential equation using the
method of variation of parameters.
y''+ 25y= sec5t
The general solution is y(t)= ___
y''+9y= csc^2(3t)
The general solution is y(t)= ___