Find the general solution to the differential equation below.
y′′ − 6y′ + 9y = 24t−5e3
Calculate the inverse Laplace transform of ((3s-2)
e^(-5s))/(s^2+4s+53)
Calculate the Laplace transform of y = cosh(at) using the
integral definition of the Laplace transform. Be sure to note any
restrictionson the domain of s. Recall that cosh(t)
=(e^t+e^(-t))/2
A) Find the general solution of the given differential equation.
y'' + 8y' + 16y = t−2e−4t, t > 0
B) Find the general solution of the given differential equation.
y'' − 2y' + y = 9et / (1 + t2)
Find the general solution of the differential equation
y′′+9y=13sec2(3t), 0<t<π/6.
Use C1, C2,... for the constants of integration. Enter an exact
answer. Enter ln|a| as ln(|a|), and do not simplify.
y(t)=
find the general solution of the given differential
equation.
1. y'' + y = tan t, 0 < t < π/2
2. y'' + 4y' + 4y = t-2 e-2t , t >
0
find the solution of the given initial value problem.
3. y'' + y' − 2y = 2t, y(0) = 0, y'(0) = 1
Find a general solution to the differential equation using the
method of variation of parameters.
y''+ 25y= sec5t
The general solution is y(t)= ___
y''+9y= csc^2(3t)
The general solution is y(t)= ___