An excellent free throw percentage would be something around 90%.

An excellent free throw percentage would be something around 90%. That is, such a basketball player would make 90% of the free throws (foul shots) they took. If the player is given 6 chances to take a free throw shot in a game.

(a) Calculate the probability that this type of player makes all 6 of their free throw shots.

(b) Calculate the probability that this type of player misses all 6 of their free throw shots.

Solutions

Expert Solution

We are given the distribution for the number of free throw shots made out of 6 as:

a) Probability that the player makes all their free throw shots is computed here as:

= p⁶

= 0.9⁶ = 0.531441

Therefore 0.531441 is the required probability here.

b) Probability that the player misses all their 6 free throws

= (1 - p)⁶

= 0.1⁶

= 0.000001

Therefore 0.000001 is the required probability here.

c) Probability that the player makes at least half of their free throws is computed here as:

Therefore 0.99873 is the required probability here.

orchestra answered 1 year ago

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