Kay has an 80% probability of making a free-throw in basketball,and each free-throw is independent....

Kay has an 80% probability of making a free-throw in basketball, and each free-throw is independent. Kay gets to take 2 free-throws, and must make both to win the game. What is the probability that Kay's team will win the game?

1. 64%

2. 80%

3. 88%

4. 160% (so 100%)

Solutions

Expert Solution

Define the events

A=Kay makes the first throw

B=Kay makes the second throw

Then P(Kay's team will win the game)=P(Kay makes both)=P(A and B)=P(A)P(B) as different throws are independent.

Now P(A)=P(B)=.80, so that

P(Kay's team will win the game)=P(Kay makes both)=P(A and B)=P(A)P(B)=.8*.8=.64

Hence the required chance is 64%.

Thus the correct option is (1).

orchestra answered 1 year ago

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