Question

Aqueous hydrobromic acid HBr reacts with solid sodium hydroxide NaOH to produce aqueous sodium bromide NaBr and liquid water H2O. What is the theoretical yield of water formed from the reaction of 79.3g of hydrobromic acid and 52.9g of sodium hydroxide? Be sure your answer has the correct number of significant digits in it.

Answer 1

HBr   + NaOH = NaBr   + H2O

first in this reaction we have to find moles of both reactents and limiting reagent

now moles of HBr = 79.3/80

                          = 0.991

moles of NaOH = 52.9/40

                        = 1.32 mole

now limiting reagent in this reaction is HBr

theartical yield = M.Wt of Product x limiting reagent weight/limiting reagent M.Wt

                          = 18 x 79.3/80

                          = 17.84 gm