Question

An L-R-C circuit has an inductance of 0.430H , a capacitance of 3.00

Answer 1

For resolve this problem must be know analysis of R-L-C circuits

Step 1:

Definition: Is an electrical circuit consisting of a resistor, an inductor, and a capacitor, connected in series or in parallel. The RLC part of the name is due to those letters being the usual electrical symbols for resistance, inductance and capacitance respectively. The circuit forms a harmonic oscillator for current and will resonate in a similar way as an LC circuit will. The main difference that the presence of the resistor makes is that any oscillation induced in the circuit will die away over time if it is not kept going by a source.

Step 2:

Equations: The angular frecuency for a circuit R-L-C is given by the following equation

  

Step 3:

ANSWER & QUESTIONS:

the expression is removed leaving

Then substituting the values

PART B: What value must R have to give a decrease in angular frequency of 11.0 rads/s compared to the value calculated in Part A?

  

The angular frecuency equation solve for R

   

We square to both side of the equality, eliminating the square root

The term pass the other side subtractingand and the term with R adding

the term pass the other side multiplicand

multiplicand

The expression the L² cancels with L, Leaving

Place square root both side of equality leaving

Substituting the value RESOLVE

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