Question

In: Chemistry

Draw the structure of XeOF4

Draw the structure of XeOF4.

Solutions

Expert Solution

By using the following steps we can draw the electron dot structures of the given molecules.

Step: 1 Count the total number of valence electrons.

Step: 2 draw the lines to represent the bonds.

Step: 3 Subtract the number of valence electrons used for bonding from the total number

calculated in step 1 to find the number that remains. Assign as many of these remaining

electrons as necessary to the terminal atoms so that each has an octet.

Step: 4 if unassigned electrons remain after step 3 place them central atom.

Step: 5 if unassigned electrons remain after step 3 but the central atom does not yet have an octet, use one or more lone pairs of electrons from a neighboring atom to form a multiple bonds.

 

The electron dot structure of \(\mathrm{XeOF}_{4}\) has:

Total number of valence electrons

\(=8 e^{-}(\) For \(\mathrm{Xe})+4 \times 7 e^{-}(\) for \(\mathrm{F})+1 \times 6 e^{-}(\) for \(\mathrm{O})\)

\(=42 \mathrm{e}^{-}\)

Therefore,

structure of XeOF4

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