Question

Draw the structure of XeOF4.

Answer 1

By using the following steps we can draw the electron dot structures of the given molecules.

Step: 1 Count the total number of valence electrons.

Step: 2 draw the lines to represent the bonds.

Step: 3 Subtract the number of valence electrons used for bonding from the total number

calculated in step 1 to find the number that remains. Assign as many of these remaining

electrons as necessary to the terminal atoms so that each has an octet.

Step: 4 if unassigned electrons remain after step 3 place them central atom.

Step: 5 if unassigned electrons remain after step 3 but the central atom does not yet have an octet, use one or more lone pairs of electrons from a neighboring atom to form a multiple bonds.

 

The electron dot structure of \(\mathrm{XeOF}_{4}\) has:

Total number of valence electrons

\(=8 e^{-}(\) For \(\mathrm{Xe})+4 \times 7 e^{-}(\) for \(\mathrm{F})+1 \times 6 e^{-}(\) for \(\mathrm{O})\)

\(=42 \mathrm{e}^{-}\)

Therefore,