Question

In: Statistics and Probability

The corporate CEO of "Life is Fun and Love is Strange Inc." claimed that the average...

The corporate CEO of "Life is Fun and Love is Strange Inc." claimed that the average sales of "Fun Life" are less than "Strange Love". In order to test the hypothesis, she asked you to conduct 2 tests. a) test the claim that the variances of the 2 stores are equal. Use a 5% significance level. b) based on your answer, use the appropriate test for the claim that the average sales of "Strange Love" are greater than "Fun Life". Use a 5% significance level for the test.

Fun Life Strange Love
9/2/19 $    10,499.94 $    15,602.13
9/9/19 $    12,570.94 $    15,266.79
9/16/19 $      3,005.02 $      4,081.42
9/23/19 $    14,248.23 $      1,382.24
9/30/19 $      8,636.75 $      8,275.37
10/7/19 $    14,204.85 $      1,245.25
10/14/19 $      9,543.69 $    10,673.07
10/21/19 $      5,263.17 $    10,464.89
10/28/19 $      7,371.62 $      8,938.07
11/4/19 $      5,008.26 $    10,442.26
11/11/19 $      3,489.96 $      2,108.36
11/18/19 $    12,743.37 $    13,724.84
11/25/19 $      1,848.10 $      9,319.00
12/2/19 $      5,789.95 $      7,755.35
12/9/19 $      7,586.66 $    12,327.17
12/16/19 $      2,287.95 $      2,343.91
12/23/19 $      3,356.14 $      2,444.49
12/30/19 $      4,558.28 $    12,514.89
1/6/20 $      7,247.02 $      4,998.70
1/13/20 $      7,374.31 $    13,333.44
1/20/20 $      4,593.70 $    14,156.07
1/27/20 $      1,792.20 $      6,646.60
2/3/20 $      3,248.34 $      3,494.17
2/10/20 $      1,372.53 $    17,622.30
2/17/20 $    11,061.58 $      8,109.53
2/24/20 $      9,250.06 $    11,629.81
3/2/20 $      3,598.44 $      1,294.15
3/9/20 $    13,069.25 $    14,609.46
3/16/20 $      1,769.34 $    16,544.91
3/23/20 $      5,340.35 $      6,791.68
3/30/20 $      9,584.29 $      9,749.47
4/6/20 $    14,422.19 $      3,744.22
4/13/20 $      4,139.96 $    11,331.56
4/20/20 $      4,917.33 $    10,489.14
4/27/20 $    12,172.46 $    17,745.47

Solutions

Expert Solution

a) test the claim that the variances of the 2 stores are equal. Use a 5% significance level.

σ₁: standard deviation of Fun Life
σ₂: standard deviation of Strange Love
Ratio: σ₁/σ₂
F method was used. This method is accurate for normal data only.

Descriptive Statistics

Variable N StDev Variance 95% CI for σ²
Fun Life 35 4112.132 1.69096E+07 (1.10635E+07, 2.90276E+07)
Strange Love 35 5023.761 2.52382E+07 (1.65127E+07, 4.33246E+07)

Ratio of Variances

Estimated
Ratio
95% CI for
Ratio using
F
0.670002 (0.338, 1.327)

Test

Null hypothesis H₀: σ₁² / σ₂² = 1
Alternative hypothesis H₁: σ₁² / σ₂² ≠ 1
Significance level α = 0.05
Method Test
Statistic
DF1 DF2 P-Value
F 0.67 34 34 0.248

The p-value is 0.248.

Since the p-value (0.248) is greater than the significance level (0.05), we fail to reject the null hypothesis.

Therefore, we can conclude that the variances of the 2 stores are equal.

b) based on your answer, use the appropriate test for the claim that the average sales of "Strange Love" are greater than "Fun Life". Use a 5% significance level for the test.

The hypothesis being tested is:

H0: µ1 = µ2

H1: µ1 < µ2

Fun Life Strange Love
7,056.1780 9,177.1480 mean
4,112.1316 5,023.7611 std. dev.
35 35 n
68 df
-2,120.97000 difference (Fun Life - Strange Love)
2,10,73,901.06583 pooled variance
4,590.63188 pooled std. dev.
1,097.37091 standard error of difference
0 hypothesized difference
-1.933 t
.0287 p-value (one-tailed, lower)

The p-value is 0.0287.

Since the p-value (0.0287) is less than the significance level (0.05), we can reject the null hypothesis.

Therefore, we can conclude that the average sales of "Strange Love" are greater than "Fun Life".


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