In the first 12.0 s of the reaction, 1.6×10−2 mol of O2 is produced in a...

In the first 12.0 s of the reaction, 1.6×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.340 L . What is the average rate of the reaction over this time interval?

Expert Solution

Molarity of O₂ , M = Number of moles / volume in L

= 1.6x10^-2 mol / 0.340 L

= 0.047 mol/L

= 0.047 M

Average rate , r = Concentration of O₂ produced / time interval

= 0.047 M / 12.0 s

= 3.92x10^-3 M/s

Therefore average rate of the reaction over this time interval is 3.92x10^-3 Ms^-1

queen_honey_blossom answered 2 years ago

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Question

In the first 12.0 s of the reaction, 1.6×10−2 mol of O2 is produced in a...

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