In: Chemistry
In the first 12.0 s of the reaction, 1.6×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.340 L . What is the average rate of the reaction over this time interval?
Molarity of O2 , M = Number of moles / volume in L
= 1.6x10-2 mol / 0.340 L
= 0.047 mol/L
= 0.047 M
Average rate , r = Concentration of O2 produced / time interval
= 0.047 M / 12.0 s
= 3.92x10-3 M/s
Therefore average rate of the reaction over this time interval is 3.92x10-3 Ms-1