In: Chemistry
This is for my biochemistry lab, the experiment is dealing with trypsin and BPTI. I need to make a graph: plot the absorbance change per minute versus the BPTI concentration for each cuvette.
here are my cuvettes and amount of BPTI added to each
1- 0uL BPTI added
2- 10 uL BPTI added
3-20 uL BPTI added
4-30 uL BPTI added
5- 40 uL BPTI added
6- 50 uL BPTI added.
Each cuvette has a different amount of water and trypsin added to them, for a total volume of 100 uL in each cuvette.
I was give a sample of BPTI for which I had to find the concentration. Using the absorbance, I calculated that the concentration was 0.035mM. We then had to dilute this 10-fold, so to 0.0035mM.
I am not sure how to find the concentration of BPTI in each cuvette with this information. The molecular weight of BPTI is 6500. I don't know if that is needed.
I feel like this should be really easy, but I am having trouble doing this.
Make a table
S.No. |
BPTI (uL) |
Water |
Trypsin |
OD |
1. |
0 |
90 |
10 |
|
2. |
10 |
80 |
10 |
|
3. |
20 |
70 |
10 |
|
4. |
30 |
60 |
10 |
|
5. |
40 |
50 |
10 |
|
6. |
50 |
40 |
10 |
BPTI molecular weight = 6500
BPTI concentration = 0.035 mM
If it is 10 fold BPTI concentration= 0.0035 mM
C1V1= C2V2
0.035 X 100 = C2 X 10
C2= 0.035 X 100/10
= 0.0035 mM
If it is 10 fold BPTI concentration= 0.00035 mM
C2= 0.035 X 100/20
= 0.175 mM
If it is 10 fold BPTI concentration= 0.0175 mM
C2= 0.035 X 100/30
= 0.00116 mM
If it is 10 fold BPTI concentration= 0.000116 mM
C2= 0.035 X 100/40
= 0.875 mM
If it is 10 fold BPTI concentration= 0.0875 mM
C2= 0.035 X 100/50
= 0.07 mM
If it is 10 fold BPTI concentration= 0.007 mM