Question

The magnetic flux through a 10.0-cm2cm2 loop is 8.0 T⋅cm2T⋅cm2, and the magnetic field at the location of the loop is uniform. Choose all correct answers.

Check all that apply.

A)If BB = 1.0 TT, then the angle between the B⃗ B→ field and the normal to the loop's surface is greater than 0∘∘.

B)If the direction of B⃗ B→ field is parallel to the normal to the loop's surface, then BB = 0.8 T.

C)The magnitude of the B⃗ B→ field must satisfy the condition B≤B≤ 0.8 T.

D) The direction of the B⃗ B→ field cannot be perpendicular to the surface of the loop.

I thought it was just B and D but apparently I'm wrong, can someone explain?

Answer 1

Magnetic flux linked with a coil is ɸ = AB Cosθ

                                Where, A – area of the coil

                                                B—magnetic field

                                                Θ—angle between the field and the normal to the plane of coil

A)

If B = 1.0 T then cosθ = ɸ/AB = 8 x 10-4 /10 x 10-4 x1= 0.8 this implies that the angle θ is greater than 0 degree

Statement A is correct

B) if B is parallel to the normal to the loop, then θ = 0 degree which implies that B = 0.8 T

Statement B is correct

C)

The statement C contradict A hence C is wrong

D)

Field B = 0.8 T if the field is perpendicular to the surface of the loop. Hence statement D is wrong

The correct statements are A and B