In: Computer Science
1)Find the equation for output F as a sum of minterms:
Inputs A, B, C | Output F |
000 | 1 |
001 | 0 |
010 | 0 |
011 | 0 |
100 | 1 |
101 | 1 |
110 | 0 |
111 | 1 |
2)Find the equation for output F in sum of product form:
3)Find the equation for output F as a product of sums:
4
Ans 1)Output F in terms of sum of minterms will be: F(A,B,C)=
Ans 2)There are 2 forms of sum of products form
1) Canonical Sum of Products which is same as sum of minterms i.e.
2) Non-canonical Sum of Products: It is reduced form of sum of minterms i.e.
Ans 3) Product of sum for F will be
F = ∏ (M1, M2, M3, M6)=(A+B+C') (A+B'+C)(A+B’+C')(A’+B’+C)
The above expression is the canonical product of sum.
The non-canonical POS is:
F=(A+B+C') (A+B'+CC')(A’+B’+C) [Distributive law]
F= (A+B+C') (A+B')(A’+B’+C) [CC'=0 complementarity law]
F= (A+B'(B+C')) (A’+B’+C) [Distributive law]
F = (A+B')(A+C')(A'+B'+C) [ BB'=0 and distributive law]
F= (A+C')(B'+A(A'+C)) [Distributive law]
F= (A+B')(A+C')(B'+C) [ AA'=0 and distributive law]
F= (A+B')(A+C')(B'+C) is the non-canonical product-of-sum.