In: Statistics and Probability
The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.02 level that the drug stays in the system for more than 331 minutes. For a sample of 87 patients, the mean time the drug stayed in the system was 335 minutes. Assume the standard deviation is known to be 23.
Step 1 of 5:
Enter the hypotheses:
Step 2 of 5:
Enter the value of the z test statistic. Round your answer to two decimal places.
Step 3 of 5:
Specify if the test is one-tailed or two-tailed.
Step 4 of 5:
Enter the decision rule.
Step 5 of 5:
Enter the conclusion.
Solution :
= 331
=335
=23
n = 87
a )This is the right tailed test .
The null and alternative hypothesis is ,
H0 : = 331
Ha : > 331
b ) Test statistic = z
= ( - ) / / n
= (335-331) / 23 / 87
= 1.62
Test statistic = z =1.62
c )P(z >1.62 ) = 1 - P(z < 1.62 ) = 1 -0.9474
P-value =0.0526
= 0.02
P-value >
0.0526 > 0.02
d )Fail to reject the null hypothesis .
e ) There is insufficient evidence to suggest that