In: Statistics and Probability
The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.05 level that the drug stays in the system for more than 399minutes. For a sample of 81patients, the mean time the drug stayed in the system was 401 minutes. Assume the population standard deviation is 21. Find the P-value of the test statistic. Round your answer to four decimal places.
Solution :
This is the right tailed test .
The null and alternative hypothesis is ,
H0 : =399
Ha : > 399
Test statistic = z
= ( - ) / / n
= (401-399) / 21/ 81
Test statistic = 0.8572 rounded 0.86
P(z > 0.86) = 1 - P(z < 0.86) = 1-0.8051=0.1949
P-value = 0.1949
=0.05
P-value >
Reject H0 :