Question

The director of research and development is testing a new drug. She wants to know if there is evidence at the 0.05 level that the drug stays in the system for more than 337 minutes. For a sample of 6 patients, the mean time the drug stayed in the system was 347 minutes with a standard deviation of 19. Assume the population distribution is approximately normal. Step 2: Find the P-value for the hypothesis test. Round your answer to four decimal places.

Answer 1

Solution :

= 337

=347

=19

n = 6

This is the right tailed test .

The null and alternative hypothesis is ,

H0 :    = 337

Ha : > 337

Test statistic = z

= ( - ) / / n

= (347-337) / 19 / 6

= 1.289

Test statistic = z = 1.29

P(z > 1.29 ) = 1 - P(z < 1.29 ) = 1 -0.9015

P-value = 0.0985

= 0.05  

P-value ≥

0.0985 ≥ 0.05

Do not reject the null hypothesis .

There is insufficient evidence to suggest that