In: Statistics and Probability
The lengths of lumber a machine cuts are normally distributed with a mean of
106106
inches and a standard deviation of
0.40.4
inch.(a) What is the probability that a randomly selected board cut by the machine has a length greater than
106.15106.15
inches?(b) A sample of
3535
boards is randomly selected. What is the probability that their mean length is greater than
106.15106.15
inches?
(a) The probability is
nothing.
(Round to four decimal places as needed.)
Solution :
Let X be a random variable which represents the lengths of lumber a machine cuts.
Given that, X ~ N(106, 0.4²)
μ = 106 inches and σ = 0.4 inch
a) We have to find P(X > 106.15).
We know that X ~ N(μ, σ²) then,
Using "pnorm" function of R we get, P(Z > 0.375) = 0.3538
Hence, the probability that a randomly selected board cut by the machine has a length greater than 106.15 inches is 0.3538.
b) We have to find P(x̅ > 106.15 inches).
We know that if X ~ N(μ, σ²) then, x̅ ~ N(μ, σ²/n).
And if x̅ ~ N(μ, σ²/n) then,
Using "pnorm" function of R we get, P(Z > 2.2185) = 0.0133
Hence, the probability that their mean length is greater than 106.15 inches is 0.0133.
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