Question

In: Statistics and Probability

a. Assume that the average weight of an NFL player is 245.7 lbs with a standard...

a. Assume that the average weight of an NFL player is 245.7 lbs with a standard deviation of 34.5 lbs. The distribution of NFL weights is not normal. Suppose you took a random sample of 32 players. What is the probability that the sample average will be greater than 250 lbs? Round your answer to three decimal places, eg 0.192.

b. Assume that the average weight of an NFL player is 245.7 lbs with a standard deviation of 34.5 lbs. The distribution of NFL weights is not normal. Suppose you took a random sample of 32 players. What is the probability that the sample average will be less than 260 lbs? Round your answer to three decimal places, eg 0.192.

Expert Solution

Solution :

Given that ,

mean = = 245.7

standard deviation = = 34.5

= / n = 34.5 / 32 = 6.0988

a.

P( > 250) = 1 - P( < 250)

= 1 - P[( - ) / < (250 - 245.7) / 6.0988]

= 1 - P(z < 0.7051)

= 1 - 0.7596

= 0.240

Probability = 0.240

b.

P( < 260) = P(( - ) / < (260 - 245.7) / 6.0988)

= P(z < 2.3447)

= 0.991

Probability = 0.991

orchestra answered 2 years ago

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