In: Statistics and Probability
The average score for games played in the NFL is 22 and the standard deviation is 9 points. 13 games are randomly selected. Round all answers to 4 decimal places where possible and assume a normal distribution.
The average score for games played in the NFL is 22 and the standard deviation is 9 points. 13 games are randomly selected. Therefore, X ~ N (22,81)
a) X ~ N (22,81) then, the distribuion of is given by,
We know if, X~N(,) then,
As,
the distribuion of is
i.e.
b) the distribution of ∑x is given by,
We know, if X~N(,) then,
Hence,
the distribution of ∑x is
i.e.
c)
= 1 - 0.128 = 0.8720 (ans)
d) 72th percentile of mean scoe,
Z score of 72th percenticde is 0.583
= 0.720
Hence, 72th percentile is 22+0.583*2.50 = 23.4575 (ans)
e)
= 0.8890 - 0.2180 = 0.6710 (ans)
f) Q1 for distribution = 25th percentile of distribution.
Hence, 25th percentile is 22+ (-0.674)*2.50 = 20.3138 (ans)
g)
= 0.477(ans)
h) Yes,for part c) and e), the assumption of normal is necessary.
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