In: Statistics and Probability
A survey of 1383 U.S. adults is taken to measure support for increasing federal funding for research on wind, solar, and hydrogen technology.
a) Suppose the sample finds 979 people who would support the increase in funding. Construct and interpret a 90% confidence interval for the proportion of all Americans that would support the funding. (assume all checks are met)
b) Currently politicians claim that between 60% and 75% of Americans would support such funding. Find the minimum sample size needed to estimate the population proportion at the 99% confidence level in order to ensure that the estimate is accurate to within 4% of the population proportion.
Let x be the the number of people who would support the increase in funding.
a) Given : x = 979 , n = 1383
Therefore = x/n = 979 / 1383 = 0.7079
confidence level = 0.90
Therefore α = 1 - 0.90 = 0.1 , 1 - (α/2) = 0.95
So we have to find z score corresponding to area 0.9500 on z score table
So z = 1.645
Confidence interval is given by,
=
=
0.6878 and 0.7280
We are 90% confident that the proportion of all Americans that would support the funding is between ( 68.78% and 72.80% )
b) Given : Lower bound = 0.60 and Upper bound = 0.75
Therefore = =
= 0.675
confidence level = 0.99 and E = 0.04
Therefore α = 1 - 0.99 = 0.01 , 1 - (α/2) = 0.995
So we have to find z score corresponding to area 0.9950 on z score table
So z = 2.575
n =
=
= 909.1208
n ~ 910
The minimum sample size needed to estimate the population proportion is 910