Question

In: Statistics and Probability

Hypothesis Test for Difference in Population Means (σσ Unknown) You wish to test the following claim...

Hypothesis Test for Difference in Population Means (σσ Unknown)

You wish to test the following claim (HaHa) at a significance level of α=0.10α=0.10.

      Ho:μ1=μ2Ho:μ1=μ2
      Ha:μ1≠μ2Ha:μ1≠μ2

You believe both populations are normally distributed, but you do not know the standard deviations for either. We will assume that the population variances are not equal.

You obtain a sample of size n1=14n1=14 with a mean of M1=78.1M1=78.1 and a standard deviation of SD1=5.6SD1=5.6 from the first population. You obtain a sample of size n2=21n2=21 with a mean of M2=84.7M2=84.7 and a standard deviation of SD2=6.9SD2=6.9from the second population.

What is the test statistic for this sample? (Report answer accurate to three decimal places.)
test statistic =

What is the p-value for this sample? For this calculation, use the conservative under-estimate for the degrees of freedom. The degrees of freedom is the minimum of n1 - 1 and n2 - 1. (Report answer accurate to four decimal places.)

p-value =

The p-value is...

  • less than (or equal to) αα
  • greater than αα



This test statistic leads to a decision to...

  • reject the null
  • accept the null
  • fail to reject the null



As such, the final conclusion is that...

  • There is sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
  • There is not sufficient evidence to warrant rejection of the claim that the first population mean is not equal to the second population mean.
  • The sample data support the claim that the first population mean is not equal to the second population mean.
  • There is not sufficient sample evidence to support the claim that the first population mean is not equal to the second population mean.

License

I am strugling to get the p-value for the being it is not equal. I am able to get the correct p-value when it is < or >

Solutions

Expert Solution

x1                     = 78.100 x2                    = 84.700
s1                     = 5.600 s2                    = 6.900
n1                    = 14 n2                    = 21
std error =√(S21/n1+S22/n2)= 2.1230
test stat t =(x1-x2-Δo)/Se = -3.109
degree of freedom v ='min(n1,n2)-1= 13
p value from excel: : = tdist(3.109,13,2)= 0.0083

The p-value is less than alpha

This test statistic leads to a decision to reject the null

The sample data support the claim that the first population mean is not equal to the second population mean.


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