Question

In: Chemistry

Calculate the molar solubility of AgI in a 0.20 M CaI2 solution.

Calculate the molar solubility of AgI in a 0.20 M CaI2 solution.

Solutions

Expert Solution

Ksp of AgI = 8.5*10^-17 check this value you book

CaI2 -----------------> Ca^2+ (aq) + 2I^- (aq)

0.2M                        0.2M               2*0.2 M = 0.4M

     AgI (s) ---------------------> Ag^+ (aq) + I^- (aq)

                                              s                  s+ 0.4

Ksp = [Ag^+][I^-]

8.5*10^-17   = s*(s+0.4)                                                            [ s<<<<<0.4   , S+ 0.4 = 0.4M]

8.5*10^-17   = s*0.4

s                  = 8.5*10^-17/0.4    = 2.125*10^-16 M

solubility of AgI is 2.125*10^-16 M

                                              


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