Calculate the molar solubility of AgI in a 0.20 M CaI2 solution.

Calculate the molar solubility of AgI in a 0.20 M CaI₂ solution.

Expert Solution

Ksp of AgI = 8.5*10^-17 check this value you book

CaI2 -----------------> Ca^2+ (aq) + 2I^- (aq)

0.2M 0.2M 2*0.2 M = 0.4M

AgI (s) ---------------------> Ag^+ (aq) + I^- (aq)

s s+ 0.4

Ksp = [Ag^+][I^-]

8.5*10^-17 = s*(s+0.4) [ s<<<<<0.4 , S+ 0.4 = 0.4M]

8.5*10^-17 = s*0.4

s = 8.5*10^-17/0.4 = 2.125*10^-16 M

solubility of AgI is 2.125*10^-16 M

queen_honey_blossom answered 1 year ago

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