Question

In: Chemistry

Calculate the pH and concentration of all species of malonic acid (C3H4O4) in each of the...

Calculate the pH and concentration of all species of malonic acid (C3H4O4) in each of the follwing solutions.

K1=1.42*10^-3, K2=2.01*10^-6

0.100 M NaC3H3O4 solution

0.100 M Na2C3H2O4 solution

Expert Solution

Ka1=1.42*10^-3

Kb1 = 1 x 10^-14 / 1.42*10^-3 = 7.04 x 10^-12

NaC3H3O4 + H2O -------------------> C3H4O4 + OH-

0.1 0 0

0.1 - x x x

Kb1 = x^2 / 0.1 - x

7.04 x 10^-12 = x^2 / 0.1 - x

x = 8.39 x 10^-7

[OH-] = 8.39 x 10^-7 M

[C3H4O4] = 8.39 x 10^-7 M

[NaC3H3O4] = 0.1 - x = 0.0999 M

pOH = -log [OH-] = -log [8.39 x 10^-7]

= 6.08

pH = 7.92

b)

Ka2 = 2.01 x 10^-6

Kb2 = 1 x 10^-14 / 2.01 x 10^-6 = 4.98 x 10^-9

C3H2O4-2 + H2O -------------------> C3H3O4- + OH-

0.1 0 0

0.1 - x x x

Kb2 = x^2 / 0.1 - x

4.98 x 10^-9 = x^2 / 0.1 - x

x = 2.23 x 10^-5

[OH-] = 2.23 x 10^-5 M

pOH = -log [OH-] = -log ( 2.23 x 10^-5)

= 4.65

pH = 9.35

queen_honey_blossom answered 1 year ago

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