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If 0.276 g of cyclohexane was obtained from 0.480 g of cyclohexanol what is the percent...

If 0.276 g of cyclohexane was obtained from 0.480 g of cyclohexanol what is the percent yield of cyclohexane? Show all calc

Expert Solution

Molar mass of cyclo hexane,C₆H₁₂ is = (6xatomic mass of C ) + ( 12 x Atomic mass of H)

= ( 6x12) + (12x1)

= 84 g/mol

Molar mass of cyclo hexane,C₆H₁₂O is = (6xatomic mass of C ) + ( 12 x Atomic mass of H)+Atomic mass of O

= ( 6x12) + (12x1)+ 16

= 100 g/mol

The chemical reaction is : Cyclohexanol cyclohexane

C₆H₁₂O C₆H₁₂

From the balanced equation ,

1 mole of C₆H₁₂ obtained from 1 mole of C₆H₁₂O

OR 84 g of C₆H₁₂ obtained from 100 g of C₆H₁₂O

M g of C₆H₁₂ obtained from 0.480 g of C₆H₁₂O

M = (0.480x84 ) /100

= 0.4032 g ----- This is the theoretical mass

Given actual mass of C₆H₁₂ obtained is 0.276 g

So percentage yield = ( actual mass / theoretical mass) x 100

= (0.276 / 0.4032) x100

= 68.4 %

Therefore the percentage yield is 68.4 %

queen_honey_blossom answered 1 year ago

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