In: Biology
In peas, axial flowers (A) are dominant over terminal flowers (a). What are the expected phenotypic ratios for the following crosses ?
a. homozygous axial x terminal
b. heterozygous axial x terminal
c. heterozygous axial x heterozygous axial
Pea plant with homozygous axial flowers (dominant) - AA
Pea plant with homozygous terminal flowers (recessive) -aa
a. cross between homozygous axial x terminal - AA x aa
A | A | |
a | Aa | Aa |
a | Aa | Aa |
The phenotype for this cross is: All pea plants will be with axial flowers which are heterozygous for the trait.
( genotype =Aa)
b. Heterozygous axial x terminal - Aa x aa
A | a | |
a | Aa | aa |
a | Aa | aa |
The progeny of this cross will be in 1:1 ratio. 50% of the plants will be with axial flowers which are heterozygous for the trait and 50% of the plants will be with terminal flowers.
c. Heterozygous axial x heterozygous axial -Aa x Aa
A | a | |
A | AA | Aa |
a | Aa | aa |
The progeny for this cross will be : Phenotypic ratio is 3: 1 ( 3pea plants with AA and Aa will be with axial flowers and i pea plant with genotype aa will be with terminal flowers).
Genotypic ratio for this cross will be: AA:aa:aa in 1:2:1 ratio. ( 1 homozygous axial flowers(AA): 2 heterozygous axial flowers(Aa): 1 terminal flowers(aa).