Refridgerant-134a with a flow rate of 0.12 kg/s is cooled to 40 degrees C at constant...

Refridgerant-134a with a flow rate of 0.12 kg/s is cooled to 40 degrees C at constant pressure in a condenser by using cooling water. Initially the refrigerant is at 1,200 kpa and 50 degrees C. Estimate the heat removed by the cooling water.

Expert Solution

temperature change of the refrigerant=T=50 C-40 C=10C

mass of refrigerant=0.12 kg/s

Heat removed by cooling water =mass *specific heat of water*T=0.12kg/s*4.186 J/g C*10C

=0.12*1000 g/s*4.186 J/g C*10C

=5023.2J/s

=5.023 KJ/s (rate of removal of heat by cooling water)

queen_honey_blossom answered 2 years ago

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