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Consider the reaction CO(g) + 3 H2 (g) ⇌ CH4 (g) + H2O(g) Kc = 7.7×10–23...

Consider the reaction CO(g) + 3 H2 (g) ⇌ CH4 (g) + H2O(g) Kc = 7.7×10–23 at 25 °C. 1.50 mol CH4 and 2.50 mol H2O are added to an empty 2.00-L container at 25 °C and allowed to reach equilibrium. What are the equilibrium amounts (in moles) of each species?

The answer is: 1.5 mol CO, 4.5 mol H2 , 1.0 mol H2O, and 2.6×10–21 mol CH4. Please include written work and explanation :-) Thank you!

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queen_honey_blossom answered 2 years ago
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