In: Statistics and Probability
The recidivism rate for convicted sex offenders is 11%. A warden suspects that this percent is lower if the sex offender is also a drug addict. Of the 352 convicted sex offenders who were also drug addicts, 32 of them became repeat offenders. What can be concluded at the αα = 0.01 level of significance?
a. We should use z test for a population proportion.
b. H0 : p = 0.11
Ha : p < 0.11
c. here sample proportion = p^ = x/n= 32/352 = 0.0910
standard error of sample proportion = sep = sqrt [0.11 * (1 - 0.11)/352] = 0.0167
z = (p^ - p)/sep = (0.0910 - 0.11)/0.0167 = -1.145
(d) p - value = P(Z < -1.145) = 0.1262
(e) the p - value is greater than alpha.
(f) we fail to reject the null hypothesis.
(g) The data suggest the population proportion is not significantly lower than 11% at αα = 0.01, so there is statistically insignificant evidence to conclude that the population proportion of convicted sex offender drug addicts who become repeat offenders is lower than 11%. Option b is correct here.
(h) If the population proportion of convicted sex offender drug addicts who become repeat offenders is 11% and if another 352 inner city residents are surveyed then there would be a 12.62% chance that fewer than 9% of the 352 convicted sex offender drug addicts in the study become repeat offenders.
(i) If the population proportion of convicted sex offender drug addicts who become repeat offenders is 11% and if another 352 convicted sex offender drug addicts are observed, then there would be a 1% chance that we would end up falsely concluding that the proportion of all convicted sex offender drug addicts who become repeat offenders is lower than 11%.
Last option is correct here.