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Maximization by the simplex method Solve the following linear programming problems using the simplex method. 1>....

Maximization by the simplex method

Solve the following linear programming problems using the simplex method.

1>.

Maximize z = x1 + 2x2 + 3x3

subject to x1 + x2 + x3 ≤ 12

2x1 + x2 + 3x3 ≤ 18

x1, x2, x3 ≥ 0

2>.

A farmer has 100 acres of land on which she plans to grow wheat and corn. Each acre of wheat requires 4 hours of labor and $20 of capital, and each acre of corn requires 16 hours of labor and $40 of capital. The farmer has at most 800 hours of labor and $2400 of capital available. If the profit from an acre of wheat is $80 and from an acre of corn is $100, how many acres of each crop should she plant to maximize her profit?

Solutions

Expert Solution

The problem is converted to canonical form by adding slack, surplus and artificial variables as appropiate

1. As the constraint-1 is of type '≤' we should add slack variable S1

2. As the constraint-2 is of type '≤' we should add slack variable S2

After introducing slack variables

Max Z = x1 + 2 x2 + 3 x3 + 0 S1 + 0 S2
subject to
x1 + x2 + x3 + S1 = 12
2 x1 + x2 + 3 x3 + S2 = 18

and x1,x2,x3,S1,S2≥0


Negative minimum Zj-Cj is -3 and its column index is 3. So, the entering variable is x3.

Minimum ratio is 6 and its row index is 2. So, the leaving basis variable is S2.

∴ The pivot element is 3.

Entering =x3, Departing =S2, Key Element =3

Negative minimum Zj-Cj is -1 and its column index is 2. So, the entering variable is x2.

Minimum ratio is 9 and its row index is 1. So, the leaving basis variable is S1.

∴ The pivot element is 2/3.

Entering =x2, Departing =S1, Key Element =2/3

Since all Zj-Cj≥0

Hence, optimal solution is arrived with value of variables as :
x1=0,x2=9,x3=3

Max Z=27


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