Question

How do you translate this pseudocode go regular code in C++

int iMin = 0,i = 0;

for(j = 0; j < n - 1; j++)

int iMin = j;

for(i = j + 1; i < n; i++)

if(a[i] < a[iMin])

iMin = i;

if(iMin != j)

swap(a[i], a[iMin]);

Answer 1

Here is the code with the proper comments:

Code:

//importing the necessary packages needed for the code
#include<bits/stdc++.h>
using namespace std;
void swap(int& x, int& y) // Function to swap the values, which is passed by reference
{
int z = x;
x = y;
y = z;
}
int main()
{
int iMin = 0,i = 0, j=0, n=0; //variable declaration
cin>> n; // taking the size of the array from the user
int a[n]; //declaration of the array
for (int k=0;k<n;k++) // taking the array values from the user and display it on screen
{
int x=0;
cin>>x;
a[k] = x;
cout<<a[k]<<" ";
}
cout<<"\n"; // leaving the space for showing the better output
  
for(j = 0; j < n - 1; j++) // Starting of your Pseudocode arrange the for loops through the brackets
{
int iMin = j;

for(i = j + 1; i < n; i++)   
{
if(a[i] < a[iMin])

iMin = i;

if(iMin != j)
  
swap(a[i], a[iMin]); // calling of the function
  
}

  
}
for (int k=0;k<n;k++) // printing the final array to see the manipulation made by the program.
{
  
cout<<a[k]<<" ";
}

}

Output:

Input from the user, the user needed to enter the array size and array elements values.

5   
9 4 5 7 2

code output for the above inputs:

9 7 5 4 2

Please see the indentation while pasting this code at your own end:

Screenshot of the running code Input and output just for the reference.

Inputs:

The functionality of the code might be converting the middle elements of the array in the descending order. But this code produces the same output as a logic shared in the form of pseudocode.