Question

Roger is a tennis player, he performs a serve with a 0.68 kg tennis racket. The serve took 0.4 s from the back of the swing until ball impact. The angular velocity of the racket at the start of the serve is zero, and it reaches a peak value equal to 29 rad^.s^-1 at the instant of ball impact. The peak linear velocity of the racket at the center of gravity is equal to 13.6 m^.s^-1.

Calculate the moment of inertia of the racket felt by the player?

Answer 1

concept --

• , where &   = angular velocity at time t & at t=0 . ,, = angular acceleration
• 
• where I = moment of inertia

Solution-- given in the question that , M= 0.68 kg , t = 0.4s , = 29 rad.s-1 , = 0 , v = 13.6m/s

• sing the equation ..
• 
• 
• 
• ..................
• now ..
• 
• putting the value ...
• ...........(1)
• now using the equatin for moment of inertia we have
• 
• 
• 
• 
• kg-m2...........(answer)