In: Computer Science
As the network administrator for a growing ISP, you want to make efficient use of your network addresses. One of the networks addresses IANA assigned to you is a Class C network of 192.168.88.0. You have decided to use the addresses in this Class C network to satisfy the IP address requirements of 18 corporate customers who need between 20 and 24 addresses each. calculate a subnet mask that meets their needs. List the subnet mask and the first four subnetwork addresses the mask will create. i need it ASAP
The Class C network 192.168.88.0 has the ability to have 254 hosts (192.168.88.1 - 192.168.88.254, due to the fact that the 192.168.88.0 is the network address and 192.168.88.255 is the network address).
If you break down the subnet mask in to binary
(11111111.11111111.11111111.00000000)
you will see that there are 8 spots here. To break this down you
will go like this
|128|64|32|16|8|4|2|1|
so you can see that the proper mask will end up being
11111111.11111111.11111111.|1|1|1|1|1|1|1|0| in binary. As this
spot will allow 26 addresses per network. It also allows for 18
networks.
To calculate that in decimal it would be 128+64+32+16+8+4+2 = 254
giving a 255.255.255.254 mask. End result 18 networks with 26
addresses per network with upto 24 usable addresses per network.
Meeting the requirements for your 16 customers, each having 20-24
addresses needed per network.
The networks will be
192.168.1.0
192.168.1.26
192.168.1.52
192.168.1.78
Each network will be able to exactly hold 24 address (because of the first and last being the network and broadcast addresses) and your mask will be 255.255.255.254.