In: Statistics and Probability
A random sample of 120 observations is selected from a binomial
population with unknown probability of success p. The computed
value of p^ is 0.69.
(1) Test H0:p≤0.6 against Ha:p>0.6. Use
α=0.05.
test statistic z=
critical zscore
The decision is
A. There is not sufficient evidence to reject the
null hypothesis.
B. There is sufficient evidence to reject the null
hypothesis.
(2) Test H0:p≥0.6 against Ha:p<0.6. Use
α=0.01
test statistic z=
critical zscore
The decision is
A. There is not sufficient evidence to reject the
null hypothesis.
B. There is sufficient evidence to reject the null
hypothesis.
(3) Test H0:p=0.6 against Ha:p≠0.6Use
α=0.05.
test statistic z=
positive critical z score
negative critical z score
The decision is
A. There is sufficient evidence to reject the null
hypothesis.
B. There is not sufficient evidence to reject the
null hypothesis.
Here p^ is 0.69 and n=120
(1) Test H0:p≤0.6 against Ha:p>0.6. Use α=0.05.
Test statistics is
The z-critical value for a right-tailed test, for a significance level of α=0.05 is
zc=1.64
Graphically
As test statistics is in rejection region we reject the null hypothesis.
Decision is B. There is sufficient evidence to reject the null hypothesis.
2. Test H0:p≥0.6 against Ha:p<0.6. Use α=0.01
Test statistics is
The z-critical value for a left-tailed test, for a significance level of α=0.05 is
zc=−1.64
Graphically
As test statistics is not in rejection area we fail to reject the null hypothesis
So decision is A. There is not sufficient evidence to reject the null hypothesis.
3. Test H0:p=0.6 against Ha:p≠0.6Use α=0.05.
Test statistics is
The z-critical values for a two-tailed test, for a significance level of α=0.05
zc=−1.96 and zc=1.96
Graphically
As test statistics is in the rejection region so we reject the null hypothesis
So Decision is A. There is sufficient evidence to reject the null hypothesis.