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Steam enters a turbine at a velocity of 200 m/s. The inlet conditions of the steam...

Steam enters a turbine at a velocity of 200 m/s. The inlet conditions of the steam are at 4000 kPA and 500°C. The diameter of the inlet pipe is 50 mm. The outlet conditions of the steam are 80 kPa and a quality of 1.0. The diameter of the outlet pipe is 250 mm. Determine the turbine power output in kJ/s assuming the kinetic energy change and potential energy change are both negligible. Calculate the change in kinetic energy to show it is indeed negligible.

Solutions

Expert Solution

Given: Inlet velocity of steam, V1=200 m/s

Inlet pressure of steam, P1=4000 kPa

Inlet temperature of steam, T1=5000C

Diameter of pipe at inlet, d1=50 mm Radius, r1=25 mm=0.025 m

Outlet pressure of steam, P2=80 kPa

Quality of steam at outlet, x2=1

Diameter of pipe at outlet, d2=250 mm Radius, r2=125 mm=0.125 m

Assumption: Heat transfer is negligible.

The energy equation for this system, neglecting the kinetic and potential energies change is

where T is the Turbine power output

is the Mass flow rate of steam

h1 and h2 is the Specific enthalpy at inlet and outlet conditions respectively

Mass flow rate of steam, , is obtained using the expression

where 1 is the Density of steam at inlet conditions,

v1 is the Specific volume of steam at inlet conditions

V1 is the Inlet velocity

A1 is the Cross sectional area of pipe at inlet, A1=r12

r1 is the Inlet radius of pipe

Refer Properties of Superheated Water Vapor Table.

At P1=4000 kPa=40 bar and T1=5000C, specific volume, v1=0.08643 m3/kg and specific enthalpy, h1=3445.3 kJ/kg.

Refer Properties of Saturated Water-Pressure table to obtain specific volume and specific enthalpy at outlet conditions.

At P2=80 kPa=0.8 bar, specific volume of saturated vapor, vg=v2=2.087 m3/kg and specific enthalpy of saturated vapor, hg=h2=2665.8 kJ/kg

Thus the turbine power output is

Thus the turbine power output is 3542.048 kJ/s.

Change in Kinetic energy, KE, is

where V2 is the Outlet velocity

Outlet velocity, V2, is obtained using the Continuity equation

where A2 is the Cross sectional area of pipe at outlet, A2=r22

r2 is the Radius of outlet pipe

2 is the Density of steam at outlet conditions,

Thus change in kinetic energy is

(Unit: kg m2/s2 is J)

Change in enthalpy, h=(3445.3-2665.3)kJ/kg=779.5 kJ/kg.

The change in kinetic energy is less than 0.1% of the enthalpy change. Hence kinetic energy change is negligible in the case of turbine.


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