Question

In: Chemistry

In order to better understand one of the most important buffer systems in our body (the...

In order to better understand one of the most important buffer systems in our body (the carbonic acid buffer system), you are titrating 0.100 L of 0.100 M carbonic acid (shown below) with 0.500 M NaOH.

What will the pH be when 23.0 mL of NaOH have been added? Please give your answer to three decimal places.

pka 1: 6.05 pka2: 10.64

Solutions

Expert Solution

moles of carbonic acid = 0.1 x 0.1 = 0.01

moles of NaOH = 0.5 x 23 / 1000 = 0.0115

pKa2 = 10.64

H2CO3 + OH- -----------------> HCO3- + H2O

0.01          0.0115                        0              0

   0             0.0015                       0.01          0.01

HCO3- + OH-   ----------------> CO32- + H2O

0.01        0.0015                            0            0

0.0085        0                                0.0015     0

here salt and acid remianed. so

pH = pKa2 + log [salt / acid]

     = 10.64 + log [0.0015 / 0.0085]

     = 9.887

pH = 9.887


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