In: Chemistry
In order to better understand one of the most important buffer
systems in our body (the carbonic acid buffer system), you are
titrating 0.100 L of 0.100 M carbonic acid (shown below) with 0.500
M NaOH.
What will the pH be when 23.0 mL of NaOH have been added? Please
give your answer to three decimal places.
pka 1: 6.05 pka2: 10.64
moles of carbonic acid = 0.1 x 0.1 = 0.01
moles of NaOH = 0.5 x 23 / 1000 = 0.0115
pKa2 = 10.64
H2CO3 + OH- -----------------> HCO3- + H2O
0.01 0.0115 0 0
0 0.0015 0.01 0.01
HCO3- + OH- ----------------> CO32- + H2O
0.01 0.0015 0 0
0.0085 0 0.0015 0
here salt and acid remianed. so
pH = pKa2 + log [salt / acid]
= 10.64 + log [0.0015 / 0.0085]
= 9.887
pH = 9.887