In: Chemistry
3. Find the pH of…
A) 0.0055 M HBr
B) 5.00 ml of LiOH after it is diluted to 500 ml
C) 2.00 M sodium benzoate (Kb = 1.5 x 10 -10)
E) Identify as acidic, basic or neutral:
KNO3 NaF NH4Cl
pH = - log [H+]
A) 0.0055 M HBr
[HBr] = [H+]= 0.0055 M
pH = - log [H+] = - log [ 0.0055] = 2.26
Therefore,
pH of 0.0055 M HBr = 2.26
B) Molarity of LiOH is required to calculate the pH.
C) Given that
[sodium benzoate] , C = 2.00 M
Kb = 1.5 x 10-10
We know that pOH = [-logKb- logC]/2
= [-log(1.5 x 10-10)- log(2)]/2
= 4.76
pOH = 4.76
Then, pH = 14- pOH = 14- 4.76 = 9.24
Therefore,
pH = 9.24
E) a) KNO3 = Neutral
KNO3 is formed from strong base KOH and strong acid HNO3. Hence, KNO3 is neutral.
b) NaF = basic
NaF is formed from strong base NaOH and weak acid HF. Hence, NaF is basic.
c) NH4Cl = acidic
NH4Cl is formed from weak base NH3 and strong acid HCl. Hence, NH4Cl is acidic.