Question

In: Chemistry

3. Find the pH of… A) 0.0055 M HBr B) 5.00 ml of LiOH after it...

3. Find the pH of…

A) 0.0055 M HBr

B) 5.00 ml of LiOH after it is diluted to 500 ml

C) 2.00 M sodium benzoate (Kb = 1.5 x 10 -10)

E) Identify as acidic, basic or neutral:

                  KNO3                                          NaF                                                                NH4Cl

Solutions

Expert Solution

pH = - log [H+]

A) 0.0055 M HBr

   [HBr] = [H+]= 0.0055 M

pH = - log [H+] = - log [ 0.0055] = 2.26

Therefore,

pH of 0.0055 M HBr = 2.26

B)   Molarity of LiOH is required to calculate the pH.

C) Given that

   [sodium benzoate] , C = 2.00 M

Kb = 1.5 x 10-10

We know that pOH = [-logKb- logC]/2

                              = [-log(1.5 x 10-10)- log(2)]/2

                              = 4.76

                     pOH = 4.76

Then, pH = 14- pOH = 14- 4.76 = 9.24

Therefore,

    pH = 9.24

E)      a) KNO3 = Neutral

            KNO3 is formed from strong base KOH and strong acid HNO3. Hence, KNO3 is neutral.

          b) NaF = basic

          NaF is formed from strong base NaOH and weak acid HF. Hence, NaF is basic.

        c) NH4Cl = acidic

         NH4Cl is formed from weak base NH3 and strong acid HCl. Hence, NH4Cl is acidic.


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