Question

In: Chemistry

In the sun, 1000g of hydrogen fuses to 993g of helium while the other 7g of...

In the sun, 1000g of hydrogen fuses to 993g of helium while the other 7g of matter is converted into energy using Einstein's famous equation E=mc2, where c is the speed of light (3.0*108m/s).

1. What is the ratio of the energy released by the fusion of 1.0 kg of hydrogen to that released by fission of 1.0 kg of Uranium-235?

2. Given the obvious advantage in energy production, briefly describe some of the difficulties in designing and operating a fusion power plant to explain why there are no commercial fusion power plants in operation today.

Solutions

Expert Solution

In fission of 1 atom of Uranium-235

3.102x10^-28 kg mass converted into energy:

Einstein's equation ;E = mc^2

E = (3.102x10^-28 Kg/atom)(3.00x10^8 m/s)^2

= 2.79x10^-12 J/atom

Now convert J/atom to kJ/mol:

(2.79x10^-12 J/atom) x [(6.022x10^23 atoms)/(1 mole)] x [(1 kJ)/(1000 J)] = 1.68x10^8 kJ/mol

Here the total mass of U -235= 1000 g , ,means number of moels = 1000 g/ 235 g/mol=4.26 mol

Now calculate the total energy= 1.68x10^8 kJ/mol *4.26 mol

= 7.2*10^8 KJ.

Now given that; In the sun, 1000g of hydrogen fuses to 993g of helium while the other 7g of matter is converted into energy.

7.0 g = 0.007 kg

Einstein's equation ;E = mc^2

E = (0.007 Kg)(3.00x10^8 m/s)^2

= 6.3*10^14 J
=6.3*10^11 KJ

Now calculate the ratio of the energy released by the fusion of 1.0 kg of hydrogen to that released by fission of 1.0 kg of Uranium-235:

6.3*10^11 KJ/ 7.2*10^8 KJ. = 875 :1

The energy released by the fusion of 1.0 kg of hydrogen : released by fission of 1.0 kg of Uranium-235:


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