Question

In: Computer Science

It is required to develop the normalization from the Relational Model for the clothing store: Modarte...

It is required to develop the normalization from the Relational Model for the clothing store: Modarte S.A. de C.V.

-Step 1: Entity-Relationship Model

The clothing store Modarte S.A. de C.V. It has various products for women, men, boys and girls, which requires generating an Entity-Relationship Model for inventory control and sales management.

It is required to develop 3 tables: products, employees and customers.

In the Products table the following fields must be considered: product code, product name, type, size, purchase date, sale date and quantity in stock.

In the Employees table, the following fields must be considered: Employee ID, Employee Name, Address, Telephone and CURP.

In the Clients table, the following fields must be considered: client number, Client name, address, e-mail, payment method, and RFC for billing.

In the Sales table the following fields must be considered: sales code, sale date, payment method and total to pay.

The Products-Sale Relationship contains the following fields: product code and sales code

- Step 2: First normal form.

- Step 3: Second normal form.

- Step 4: Third normal form.

Solutions

Expert Solution

Table with fields

Products – productCode(PK),productName,type,size,purchaseDate,saleDate,quantity

Employees – employeeId(PK),employeeName,address,phone,curp

Clients – clientNumber(PK),clientName,address,email,payMthod,rfc

Sales – salesCode(PK),saleDate,payMethod,totalPay

Entity-Relationship Model

First Normal Form [1NF]

A database is in first normal form if it satisfies the following conditions:

  • Contains only atomic values
  • There are no repeating groups

In the Employee table address, phone are multi valued attributes. If the table should be like this:

employeeId

employeeName

Address

Phone

Curp

101

James

First street plot no 4

9845673489, 9645677832

J237801

102

Peter

Park avenue flat no 123

945239876

P25678

According to 1NF the above table must be like this:

employeeId

employeeName

Address

Phone

Curp

101

James

First street plot no 4

9845673489

J237801

101

James

First street plot no 4

9645677832

J237801

102

Peter

Park avenue flat no 123

945239876

P25678

In the client table email attribute is multi-valued attribute. So that should be also split like above table.

Second Normal Form

· In the 2NF, relational must be in 1NF.

· In the second normal form, all non-key attributes are fully functional dependent on the primary key

productCode

productName

Type

Size

purchaseDate

saleDate

quantity

1001

Shirt

Cotton

40

12/10/2020

10/11/2020

5000

1001

Shirt

Cotton

40

12/10/2020

12/11/2020

3000

1001

Shirt

Cotton

40

12/10/2020

20/11/2020

2500

The above table can be split like below:

productCode

productName

Type

Size

purchaseDate

Quantity

1001

Shirt

Cotton

40

12/10/2020

5000

1001

Shirt

Cotton

40

12/10/2020

3000

1001

Shirt

Cotton

40

12/10/2020

2500

productCode

productName

Type

Size

saleDate

quantity

1001

Shirt

Cotton

40

10/11/2020

5000

1001

Shirt

Cotton

40

12/11/2020

3000

1001

Shirt

Cotton

40

20/11/2020

2500

Third Normal Form

  • A relation will be in 3NF if it is in 2NF and not contain any transitive partial dependency.
  • 3NF is used to reduce the data duplication. It is also used to achieve the data integrity.
  • If there is no transitive dependency for non-prime attributes, then the relation must be in third normal form.

A relation is in third normal form if it holds atleast one of the following conditions for every non-trivial function dependency X Y.

  1. X is a super key.
  2. Y is a prime attribute, i.e., each element of Y is part of some candidate key.

employeeId

employeeName

Address

Phone

Curp

101

Sherin

Third cross no 12

9654329874

S78654

102

James

First street plot no 4

9645677832

J237801

103

Peter

Park avenue flat no 123

945239876

P25678

FD set:


{employeeId -> employeeName, employeeId -> phone, employeeId -> curp, employeeId -> address}

Candidate Key:


{employeeId}


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