How many milliliter a of 1.0 M NaOH must be added to a 200 mL of...

How many milliliter a of 1.0 M NaOH must be added to a 200 mL of 0.10 M NaH2PO4 to make a buffer solution with a pH of 7.50?

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Expert Solution

200 mL* 0.10 M H2PO4^- = 200*0.1 = 20 millimols.
----mL* 1.0 M NaOH = ---- millimoles.

H2PO4^- + OH^- ==> HPO4^- + H2O
20 0 0 initial

-x -x x change
20-x 0 x equilibrium

pH = pKa + log[(base)/(acid)]

7.50 = 6.86 + log(x/20-x)

x = 16.27 mL

7.50 = 6.86 + log(x/20-x)

queen_honey_blossom answered 1 year ago

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