Question

In: Chemistry

how much 6.00 m naoh must be added to 610.0 ml of a buffer that is...

how much 6.00 m naoh must be added to 610.0 ml of a buffer that is 0.0185 m acetic acid ad 0.0235 m sodium acetate to raise the ph to 5.75?

Expert Solution

no of mmole of CH3COOH = molarity*volume in ml

= 0.0185*610 = 11.285mmole

no of mmoles of CH3COONa = molarity*volume in ml

= 0.0235*610 = 14.335 mmoles

no of mmoles of NaOH = molarity*volume in ml

= 6*x = 6x mmoles

CH3COOH + NaOH -----------------> CH3COONa + H2O

I 11.285 6x 14.335

C -6x 0 +6x

E 11.285-6x 0 14.335+6x

PH = PKa + log[CH3COONa]/[CH3COOH]

5.75 = 4.75 + log(14.335+6x)/(11.285-6x)

log(14.335+6x)/(11.285-6x) = 5.75-4.75

log(14.335+6x)/(11.285-6x) = 1

(14.335+6x)/(11.285-6x) = 10

(14.335+6x) = 10*(11.285-6x)

x = 1.49

x = 1.49ml

volume of NaOH = 1.49ml

queen_honey_blossom answered 2 years ago

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