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Hi, I would like the numerical solution for this task so I can be able to...

Hi,

I would like the numerical solution for this task so I can be able to model it in a kinetic modeling programme like Berkely Madonna (BM). This was the reason why I started my membership with Chegg Study but unfortunately, the solution to this problem was not available. I'm looking forward to hearing from you.

you will find the task in de link below.

With kind regards,

Ahmed

https://www.chegg.com/homework-help/comprehensive-problem-multiple-reactions-heat-effects-styren-chapter-12-problem-24qp-solution-9780132317160-exc

in J.Snyder en B.Subramaniam, Chem. Eng. Sci., 49, 5585 (1994).

the simulation is :

{ simulatie van ethyleenproductie }

{ balance }
Kp1 = exp(b1+b2/T+b3*logn(T)+b4*T^3+b5*T^2+b6*T)
b1 = -581e-2
b2 = -13020
b3 = 5051e-3
b4 = -2314e-13
b5 = 1302e-9
b6 = -4913e-6

{ reaktor }
T = 900   {K}
Pbar = 2.3   {bar}
P = Pbar*1e5   {Pa}

{ kinetics }
r1S = k1*(Peb-Ps*Ph2/Kp1)
k1 = 1.177*exp(-21708/(R*T))
r2B = k2*Peb
k2 = 200.2*exp(-49675/(R*T))
r3T = k3*Peb*Ph2
k3 = 0.4789e-6*exp(-21857/(R*T))

{ variables }
Peb = yeb*P
Ps = ys*P
Ph2 = yh2*P

yeb = Neb/Ntot
ys = Ns/Ntot
yh2 = Nh2/Ntot

{ equations }
Ntot = Neb+Ns+Nh2

{ feed }
Neb0 =

Solutions

Expert Solution

Part-a) Here we represent the given reactions as

where A is ethylbenzene, B is styrene, C is hydrogen, D is benzene, E is ethylene, F is toluene and G is methane.

These differential equations can be solved easily with polymath as shown below.

Part-b) for To=930 K

Part-c) for To=1100 K

Part-d) Molar flowrate of styrene versus To gives the ideal inlet temperature as 995 K as shown below.

Part-e) By plotting the molar flowrate of Styrene as a function of steam to ethylebenzene ratio gives the ideal ratio at 900 K as 25:1 as shown below.

Part-f)


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