Question
In: Chemistry
What is the overall lifetime, in seconds, of hydroperoxy radicals in the polluted troposphere where [O3]...
What is the overall lifetime, in seconds, of hydroperoxy radicals in the polluted troposphere where [O3] is 100 ppb and [NO] is 20 ppb? Repeat the calculation for the clean troposphere where [O3] is 30 ppb and [NO] is 0.002 ppb. Use the following reactions and rate constants.
HO2 + NO → NO2 + OH k = 8.1x10-12 cm3 s-1
HO2 + O3 → 2O2 + OH k = 7.3x10-14 exp(-1275/T) cm3 s-1
Solutions
Expert Solution
- HO2 + NO NO2 + OH
K = 8.1 X 10-12 cm3/s
Overall life time
T = 1/ K [NO]
T = 1/ 8.1 X 10-12 X 20
= 6.17 X 108 sec
Overall life time
T = 1/ K [NO]
T = 1/ 8.1 X 10-12 X 0.002
= 61.7 X 1012 sec
- HO2 + O3 2O2 + OH
K = 7.3 X 10-14 cm3/s
Overall life time
T = 1/ K [O3]
T = 1/ 7.3 X 10-14 X 100
= 1.36 X 108 sec
Overall life time
T = 1/ K [O3]
T = 1/ 7.3 X 10-14 X 30
= 4.57 X 1010 sec
queen_honey_blossom answered 1 year agoRelated Solutions
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