Question

In: Statistics and Probability

simple random sample of 80 customers is taken from a customer information file and the average...

  1. simple random sample of 80 customers is taken from a customer information file and the average age is 34. The population standard deviation σ is unknown. Instead the sample standard deviation s is also calculated from the sample and is found to be 5.5. (6 points)
    1. Test the hypothesis that the population mean age is greater than 30 using the critical value approach and a 0.05 level of significance.
    2. Test the hypothesis that the population mean age is less than 37 using the p-value approach and a 0.05 level of significance.
    3. Test the hypothesis that the population mean age is different from 31 using the p-value approach and a 0.05 level of significance.

Solutions

Expert Solution

a)
Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ = 30
Alternative Hypothesis, Ha: μ > 30

Rejection Region
This is right tailed test, for α = 0.05 and df = 79
Critical value of t is 1.664.
Hence reject H0 if t > 1.664

Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (34 - 30)/(5.5/sqrt(80))
t = 6.505


reject the null hypothesis


b)

Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ = 37
Alternative Hypothesis, Ha: μ < 37

Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (34 - 37)/(5.5/sqrt(80))
t = -4.879

P-value Approach
P-value = 0
As P-value < 0.05, reject the null hypothesis.

c)

Below are the null and alternative Hypothesis,
Null Hypothesis, H0: μ = 31
Alternative Hypothesis, Ha: μ ≠ 31

Test statistic,
t = (xbar - mu)/(s/sqrt(n))
t = (34 - 31)/(5.5/sqrt(80))
t = 4.879

P-value Approach
P-value = 0
As P-value < 0.05, reject the null hypothesis.



Related Solutions

A simple random sample of 20 customers is taken from a customer information file and the...
A simple random sample of 20 customers is taken from a customer information file and the average age is 27. The sample standard deviation s is found to be 5.                                              (5 marks) Test the hypothesis that the population mean age is less than 29 using the critical value approach and a 0.10 level of significance. Test the hypothesis that the population mean age is different from 30 using the 0.05 level of significance.
A simple random sample of 20 customers is taken from a customer information file and the...
A simple random sample of 20 customers is taken from a customer information file and the average age is 27. The sample standard deviation s is found to be 1.5.                                                 (5 marks) Test the hypothesis that the population mean age is less than 29 using the critical value approach and a 0.10 level of significance. Test the hypothesis that the population mean age is different from 30 using the 0.05 level of significance. .
A random sample of 29 lunch customers was taken at a restaurant The average amount of...
A random sample of 29 lunch customers was taken at a restaurant The average amount of time the customers in the sample stayed in the restaurant was 45 minutes with a standard deviation of 14 minutes. a) Compute the standard error of the mean? b) Construct a 68% confidence interval for the true average amount of time customers spent in the restaurant? c) Construct a 90% confidence interval for the true average amount of time customers spent in the restaurant?...
A random sample of 49 lunch customers was taken at a restaurant. The average amount of...
A random sample of 49 lunch customers was taken at a restaurant. The average amount of time these customers stayed in the restaurant was 45 minutes with a standard deviation of 14 minutes. a. Compute the standard error of the mean. b. Construct a 95% confidence interval for the true average amount of time customers spent in the restaurant. c. With a .95 probability, how large of a sample would have to be taken to provide a margin of error...
A random sample of 49 lunch customers was taken at a restaurant. The average amount of...
A random sample of 49 lunch customers was taken at a restaurant. The average amount of time these customers stayed in the restaurant was 45 minutes with a sample standard deviation of 14 minutes. Compute the standard error of the mean. At 95% confidence, what is the confidence interval estimate? Construct a 99% confidence interval for the true average amount of time customers spent in the restaurant. Compare the margin of errors and width of your confidence intervals from parts...
simple random sample of 80 items from a population with = 8 resulted in a sample...
simple random sample of 80 items from a population with = 8 resulted in a sample mean of 38. If required, round your answers to two decimal places. a. Provide a 90% confidence interval for the population mean. to b. Provide a 95% confidence interval for the population mean. to c. Provide a 99% confidence interval for the population mean. to
The manager of a grocery store has taken a random sample of 100 customers. The average...
The manager of a grocery store has taken a random sample of 100 customers. The average length of time it took the customers in the sample to check out was 4.8 minutes with a sample standard deviation of 0.5 minutes. Conduct a test to determine whether or not the mean waiting time of all customers is significantly more than 5 minutes. Use a significance level of α = 0.01.
A simple random sample of 25 observations will be taken from a population that is assumed...
A simple random sample of 25 observations will be taken from a population that is assumed to be normal with a standard deviation of 37. We would like to test the alternative hypothesis that the standard deviation is actually more than 37. If the sample standard deviation is 40 or more, then the null hypothesis will be rejected (this called a decision rule). What significance level would this decision rule cause? If the population standard deviation is really 42, what...
In a simple random sample of size 50, taken from a population, 23 of the individuals...
In a simple random sample of size 50, taken from a population, 23 of the individuals met a specified criteria. a) What is the margin of error for a 90% confidence interval for p, the population proportion? Round your response to at least 3 decimal places.     b) What is the margin of error for a 95% confidence interval for p? Round your response to at least 3 decimal places.    
The following data is for a simple random sample taken from a normal population: 2.41 2.45...
The following data is for a simple random sample taken from a normal population: 2.41 2.45 2.21 2.32 2.25 2.38 (a) Find a 95% prediction interval. (b) Find a tolerance interval that contains 90% of the data with 95% confidence
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT