In: Statistics and Probability
You may need to use the appropriate appendix table or technology to answer this question.
Consider the following hypothesis test.
H0: μ ≥ 20
Ha: μ < 20
A sample of 50 provided a sample mean of 19.1. The population standard deviation is 2.
(a)
Find the value of the test statistic. (Round your answer to two decimal places.)
(b)
Find the p-value. (Round your answer to four decimal places.)
p-value =
(c)
Using
α = 0.05,
state your conclusion.
Reject H0. There is sufficient evidence to conclude that μ < 20.Reject H0. There is insufficient evidence to conclude that μ < 20. Do not reject H0. There is sufficient evidence to conclude that μ < 20.Do not reject H0. There is insufficient evidence to conclude that μ < 20.
(d)
State the critical values for the rejection rule. (Round your answer to two decimal places. If the test is one-tailed, enter NONE for the unused tail.)
test statistic≤test statistic≥
State your conclusion.
Reject H0. There is sufficient evidence to conclude that μ < 20.Reject H0. There is insufficient evidence to conclude that μ < 20. Do not reject H0. There is sufficient evidence to conclude that μ < 20.Do not reject H0. There is insufficient evidence to conclude that μ < 20.
Solution :
= 20
= 19.1
= 2
n = 50
This is the left tailed test .
The null and alternative hypothesis is
H0 : ≥ 20
Ha : < 20
a) Test statistic = z
= ( - ) / / n
= (19.1 - 20) / 2 / 50
= -3.18
b) P (Z < -3.18) = 0.0007
P-value = 0.0007
= 0.05
0.0007 < 0.05
c)Reject H0. There is sufficient evidence to conclude that μ < 20.
d) = 0.05
The left tailed critical value is -1.65
Reject H0. There is sufficient evidence to conclude that μ < 20