Question

In: Statistics and Probability

You may need to use the appropriate appendix table or technology to answer this question. Consider...

You may need to use the appropriate appendix table or technology to answer this question.

Consider the following hypothesis test.

H0: μ ≥ 20

Ha: μ < 20

A sample of 50 provided a sample mean of 19.1. The population standard deviation is 2.

(a)

Find the value of the test statistic. (Round your answer to two decimal places.)

(b)

Find the p-value. (Round your answer to four decimal places.)

p-value =

(c)

Using

α = 0.05,

state your conclusion.

Reject H0. There is sufficient evidence to conclude that μ < 20.Reject H0. There is insufficient evidence to conclude that μ < 20.     Do not reject H0. There is sufficient evidence to conclude that μ < 20.Do not reject H0. There is insufficient evidence to conclude that μ < 20.

(d)

State the critical values for the rejection rule. (Round your answer to two decimal places. If the test is one-tailed, enter NONE for the unused tail.)

test statistic≤test statistic≥

State your conclusion.

Reject H0. There is sufficient evidence to conclude that μ < 20.Reject H0. There is insufficient evidence to conclude that μ < 20.     Do not reject H0. There is sufficient evidence to conclude that μ < 20.Do not reject H0. There is insufficient evidence to conclude that μ < 20.

Solutions

Expert Solution

Solution :

= 20

= 19.1

= 2

n = 50

This is the left tailed test .

The null and alternative hypothesis is

H0 :   ≥ 20

Ha : < 20

a) Test statistic = z

= ( - ) / / n

= (19.1 - 20) / 2 / 50

= -3.18

b) P (Z < -3.18) = 0.0007

P-value = 0.0007

= 0.05  

0.0007 < 0.05

c)Reject H0. There is sufficient evidence to conclude that μ < 20.

d) = 0.05  

The left tailed critical value is -1.65

Reject H0. There is sufficient evidence to conclude that μ < 20


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