Determine Kb for the nitrite ion, NO2-. In a 0.10-M solution, this base is 0.0015% ionized.

Expert Solution

The ionization equation of nitrite ion will be

NO2- + H2O --> HNO2 + OH-

Initial 0.1 0 0

Change -x x x

Equilibrium 0.1-x x x

x = 0.0015 X 0.1 / 100 = 0.00000015

Kb = [HNO2] [ OH-] / [NO2-]

Kb = 0.00000015 X 0.00000015 / 0.1 -0.00000015 =

Kb = 2.25 X 10^-11

queen_honey_blossom answered 2 years ago

Draw the best Lewis structure for the nitrite ion, NO2– .

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