In: Chemistry
The hydronium ion concentration of an aqueous solution of
0.530 M hydroxylamine (a weak base with
the formula NH2OH) is ...
[H3O+] = ____M
kb of hydroxylamine = 1.1*10^-8
NH2OH dissociates as:
NH2OH +H2O
-----> NH2+ +
OH-
0.53
0 0
0.53-x
x x
Kb = [NH2+][OH-]/[NH2OH]
Kb = x*x/(c-x)
Assuming x can be ignored as compared to c
So, above expression becomes
Kb = x*x/(c)
so, x = sqrt (Kb*c)
x = sqrt ((1.1*10^-8)*0.53) = 7.635*10^-5
since c is much greater than x, our assumption is correct
so, x = 7.635*10^-5 M
use:
[H3O+] = (1.0*10^-14)/[OH-]
[H3O+] = (1.0*10^-14)/7.635443667528429E-5
[H3O+] = 1.31*10^-10
Answer: 1.31*10^-10 M