Question
In: Chemistry
A 10.00 mL solution of 0.0500 M AgNO3 was titrated with 0.0250 M NaBr in the...
A 10.00 mL solution of 0.0500 M AgNO3 was titrated with 0.0250 M NaBr in the cell: S.C.E.(saturated calomel electrode) titration solution Ag (s). (Ksp AgBr(s) = 5.0e-13)
Find the cell voltage (v) when the volume of titrant added is 5.00 ml.
Find the equivalence volume (ml) of titrant added.
Calculate the cell voltage (v) when the volume of titrant added is 24.58 ml
Calculate the cell voltage (v) at the equivalence point.
.
Solutions
Expert Solution
Solution.
The scheme of the cell is S.C.E.|| titration solution | Ag(s)
Therefore, the cell voltage is 
When 5 mL of the titrant is added, the concentration of silver ions is
The cell voltage is 
The equivalence volume of titrant added can be found as
The cell voltage at the equivalence point will be determined by a solubility of AgBr.
The cell voltage is 
When 24.58 mL of titrant has been added, the concentration of bromide-ions is
The concentration of silver ions is
The cell voltage is 
queen_honey_blossom answered 2 years agoRelated Solutions
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