A 10.00 mL solution of 0.0500 M AgNO3 was titrated with 0.0250 M NaBr in the...

A 10.00 mL solution of 0.0500 M AgNO3 was titrated with 0.0250 M NaBr in the cell: S.C.E.(saturated calomel electrode) titration solution Ag (s). (Ksp AgBr(s) = 5.0e-13)

Find the cell voltage (v) when the volume of titrant added is 5.00 ml.

Find the equivalence volume (ml) of titrant added.

Calculate the cell voltage (v) when the volume of titrant added is 24.58 ml

Calculate the cell voltage (v) at the equivalence point.

Solutions

Expert Solution

Solution.

The scheme of the cell is S.C.E.|| titration solution | Ag(s)

Therefore, the cell voltage is

When 5 mL of the titrant is added, the concentration of silver ions is

The cell voltage is

The equivalence volume of titrant added can be found as

The cell voltage at the equivalence point will be determined by a solubility of AgBr.

The cell voltage is

When 24.58 mL of titrant has been added, the concentration of bromide-ions is

The concentration of silver ions is

The cell voltage is

queen_honey_blossom answered 1 year ago

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